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x = \frac{-b \pm \sqrt{b^2 – 4ac}}{2a}
\int_0^\infty e^{-x^2} \, dx = \frac{\sqrt{\pi}}{2}
\sum_{n=1}^\infty \frac{1}{n^2} = \frac{\pi^2}{6}
E = mc^2
\lim_{x \to 0} \frac{\sin x}{x} = 1
\int_0^\infty e^{-x^2} \, dx = \frac{\sqrt{\pi}}{2}
\sum_{n=1}^\infty \frac{1}{n^2} = \frac{\pi^2}{6}
E = mc^2
\lim_{x \to 0} \frac{\sin x}{x} = 1